Some c++ help

[mazoo]

I currently creating a bot in C++ but I've ran into a probelm,
When I want to change the title of the clinent using SetWindowText I don't know how to make the output as I like :S
Want it to be like -> "1920 exp to next Level."

I've tried things like SetWindowText(<my_handle>, exp + "to next Level."); but I'm affraid that my C++ skills ain't too good xD

Any help will be greeted.

[zionz]

There are many ways to do this, i prefer this one (more C than C++ tough):



char msg[512];
sprintf(msg,"%i + to next Level.", exp);
SetWindowText(<my_handle>, msg);

[Kekke]

Easier and safer(?) way the way I like it:




#include <iostream>
#include <sstream>

using namespace std;

int main()
{
int exp = 512; //declares
string msg;
stringstream buffer;

buffer << exp; //transfer exp to stringstream
buffer >> msg; //transfer the stringstream to msg (a string)

msg += " exp to new level"; //append the text to our string

cout << msg << endl; // cout it, here is where you setwindowtext it.
cin.get();
}


As I thought:



Most buffer overflow problems in C can be traced directly back to the standard C library. The worst culprits are the problematic string operations that do no argument checking (strcpy, strcat, sprintf, gets).

[zionz]

Kekke is right, that way is much safer, but if you want it safe in C you can always use snprintf(), about speed, i think the c version will be much faster, but if speed is not an issue, then always use the safest method.

[mazoo]

Thanks! Problem solved.

[rand0m_]

Or you could just do something like:
SetWindowText(<my_handle>, (exp + " experience left.") );

:p

[zionz]

Or you could just do something like:
SetWindowText(<my_handle>, (exp + " experience left.") );

:p

That wont work in c++, SetWindowText takes a char* as a parameter (guessing that exp is a string class in that example)

[rand0m_]

That wont work in c++, SetWindowText takes a char* as a parameter (guessing that exp is a string class in that example)


Hmm? when using (exp + " experience left.") it creates a string. If you'd have some experience with strings and chars et c, you would know that you can use the "c_str()" function to convert this string into the correct type. :D

[zionz]

I know but you first have to convert exp (int) to a string and thats the original problem :p.

You mean this way?:



#include <iostream>

using namespace std;

int main()
{
string cexp = "100";

printf((cexp + " left").c_str());
return 0;
}


Or you say that cexp being int will allow you to do the same?

[Kekke]

Yeah.. exp will most likely be an int.